Infinity * Zero = Any Number ARGUE HERE

**eagleboy** · 01-4-2007, 06:52 AM

Re: Infinity * Zero = Any Number ARGUE HERE

Originally posted by Vests

Infinity isnt a real number though. It is called a imaginary number, as it isn't definate thus it technicly doesn't exist that is also why no mathmatical theorum besides ones made up by idiots use infinity.

That's right. Infinity is as imaginary as the number i. I is used to define the square root of (-1). Adding i to any real number would simply create a complex imaginary number, as would multiplication, division, and subtraction. It's impractical to use it to solve real-life equations, as who really uses i and infinty in daily life anyway? Scientists and mathematicians, but they don't always have the best grasp of it anyway.

On that matter:

i^2 = (-1)

i^3 = (-i)

i^4 = 1

i^5 = i

i^(|4-x|) = (y)

For x (> or =) 0 and {x U Z}
If |4-x| = 3
And x < 4
Then y = i
Else
y = (-i)
ElseIf |4-x| = 2
Then y = (-1)
ElseIf |4-x| = 1
And x < 4
Then y = (-i)
Else
y = i
Else
y = 1
EndIf
EndFor

**RoyalCat** · 01-4-2007, 07:41 AM

Re: Infinity * Zero = Any Number ARGUE HERE

Infinity= I
Any Number= A

0*I=A
(0*I)^2=A^2

(0*I)^2= 0*0+0*I+0*I+I*I=I^2

I^2=A^2?
I=A?
Assuming that A is 0 then Infinity is 0. Or rather we can give infinity any value which would no longer make it infinity as someone previously stated, it isn't a real number. Then again that would break the premise for my whole calcluations since they regard the rules of math that work on actual numbers.

Going further;
0+I=I
(0+I)^2 is supposed to equal I^2

(0+I)^2= 0^2+2A+I^2= 2A+I^2

I^2= 2A+I^2
2A=0

Since 2 equals 2 which is not 0, then A must equal 0. Therefore, any number is always 0. Quite a big flaw.

Just some random thought. o_o

**Fry** · 01-4-2007, 08:25 AM

Re: Infinity * Zero = Any Number ARGUE HERE

Originally posted by RoyalCat

(0*I)^2= 0*0+0*I+0*I+I*I=I^2

You assumed 0*I = 0 here.

**darkdieuguerre** · 01-4-2007, 01:07 PM

Re: Infinity * Zero = Any Number ARGUE HERE

You can't perform normal operations (addition, subtraction etc.) with infinity. L'H�pital's rule says that infinity minus infinity can be any number, infinity divided by infinity can be any number, zero times infinity can be any number, and other examples. (Actually, L'H�pital's rule dictates how to evaluate "indeterminate" limits, but those limits are of forms which usually involve infinity). Therefore, RoyalCat's proofs are invalid.

**RoyalCat** · 01-4-2007, 02:06 PM

Re: Infinity * Zero = Any Number ARGUE HERE

darkdieuguerre, I think I'd be better prepared to argue here if I knew how to PRONOUNCE L'H�pital. o_o; I'm assuming he's some french mathematician that dealt with the subject of infinity?

According to how you quoted him, Infinity is a number outside of the numeric system that we usually use and that therefore none of the axiomes that we have in place affect it. Am I correct in phrasing that?

**talisman** · 01-4-2007, 03:07 PM

Re: Infinity * Zero = Any Number ARGUE HERE

infinity is not a number it is a concept

there are various operations with infinity that are undefined

there are various operations with infinity that are defined

one operation that is undefined is infinity multiplied by zero

please accept this.

**tha Guardians** · 01-4-2007, 03:39 PM

Re: Infinity * Zero = Any Number ARGUE HERE

Originally posted by RoyalCat

Infinity= I
Any Number= x

0*I=x
(0*I)^2=x^2

(0*I)^2= 0*0+0*I+0*I+I*I=I^2

I^2=x^2?
I=x?
Assuming that x is 0 then Infinity is 0. Or rather we can give infinity any value which would no longer make it infinity as someone previously stated, it isn't a real number. Then again that would break the premise for my whole calcluations since they regard the rules of math that work on actual numbers.

Going further;
0+I=I
(0+I)^2 is supposed to equal I^2

(0+I)^2= 0^2+2x+I^2= 2x+I^2

I^2= 2x+I^2
2x=0

Since 2 equals 2 which is not 0, then x must equal 0. Therefore, any number is always 0. Quite a big flaw.

Just some random thought. o_o

How does I*0=0? If you remove infinity from infinity, is it no longer infinity?

Originally posted by Early Indian History, The Yajur Veda (1200-900 B.C.)

Om Poorna mada poorna midam (Om, that is full, this is full) Poornad poorna mudachyate (From that full, this full is removed) Poornasaya poornamadaya Poornameva vasishyate (Yet the full remains full always)"

It's like saying x-y=x=y, but x=I and y=I (sorry for expressing I with a variable, I realize that is incorrect)

I-I=/=0, I-I=?x or I-I=?I (but in my opinion, I-I=0+x = I-I=x because I (being me) believe Infinity = I+n^I (I has no limit, not because no limit is set, but because the limit increases infinitely)

I*2=2I, 2I=I, I*2=I

When you say Infinity zero times equals any number, do you say that because you don't know what Infinity zero times is?

(0^2=0)

2x+
(I^I=I, for infinity has no limit and shall always remain infinity)=
2x+I

EDIT: Please note that my theories are solely opinion and do not regard anyone other than myself and I do not state them as fact; only pure opinion.

**darkdieuguerre** · 01-4-2007, 03:44 PM

Re: Infinity * Zero = Any Number ARGUE HERE

Originally posted by RoyalCat

darkdieuguerre, I think I'd be better prepared to argue here if I knew how to PRONOUNCE L'H�pital. o_o; I'm assuming he's some french mathematician that dealt with the subject of infinity?

According to how you quoted him, Infinity is a number outside of the numeric system that we usually use and that therefore none of the axiomes that we have in place affect it. Am I correct in phrasing that?

If you read my post, you'd see that L'H�pital's rule tells you how to deal with indeterminate limits. Actually, he didn't do any of the work, if memory serves me right.

Infinity is not a number, as has been stated before. Since it isn't a number, it can't be used in mathematical operations.

**tha Guardians** · 01-4-2007, 04:31 PM

Re: Infinity * Zero = Any Number ARGUE HERE

Originally posted by Shashakiro

TI-89 is wrong if it says that, although I'd like to check it out on mine...you're using the actual infinity key, right?

0*0 is always 0, no matter how many times
1*1 is always 1, no matter how many times

**RandomPscho** · 01-4-2007, 05:42 PM

Re: Infinity * Zero = Any Number ARGUE HERE

For the infinity - infinaty think of it as anything - anything = anything

Anything could be anything, but it is defined as a certain something so you are subtracting to random things that will equal another thing which is also undefined

**3D OGRE 1** · 01-4-2007, 10:50 PM

Re: Infinity * Zero = Any Number ARGUE HERE

it's all relative... you think 1+1=2? hahaha..WRONG

**eagleboy** · 01-5-2007, 06:33 AM

Re: Infinity * Zero = Any Number ARGUE HERE

Originally posted by tha Guardians

1^x = 1^1(x) and if x=0 then 1^1(0)=0 so no... 1^x=/=1 if I'm correct.
1^1 = 1
x^0 = 1

Sorry.

You're inaccurate with that statement. 1^0 is actually still 1.

1^x DOES NOT always equal 1, but these factors only work in when (x U Z) and x is -(an odd number)

Example:

1^(-3) = (-1) because (-1)(-1)(-1) = (-)(-)(-) which = (+)(-) which is obviously = to (-).

Actually, for x < 0, 1^x is undefined unless (x U Z).

For those who don't know this, (x U Z) means that x is an integer (but not necessarily a positive one).

**************
EDIT**********
**************

Also, x^0 is not always = to 1. 0^0 = 0 is an easy disproval.

Then I re-read and see your three statements contradict each other.

Originally posted by tha Guardians

1^x = 1^1(x) and if x=0 then 1^1(0)=0 so no... 1^x=/=1 if I'm correct.
1^1 = 1
x^0 = 1

First of all, 1^x = 1^((1)x), not 1^1(x). You're displacing the x so that it no longer signifies the power, but in essentiality you're saying that 1^x is basically equal to x.

Secondly, and most importantly, your first and third "facts" are saying that 1^0 = 0, yet x^0 = 1. WTF, man; please read what you type before you click the final post.

**darkdieuguerre** · 01-5-2007, 02:02 PM

Re: Infinity * Zero = Any Number ARGUE HERE

Originally posted by RandomPscho

For the infinity - infinaty think of it as anything - anything = anything

Anything could be anything, but it is defined as a certain something so you are subtracting to random things that will equal another thing which is also undefined

Isn't that a bad analogy? By saying that infinity - infinity can be anything - anything, you basically equate infinity to anything, which is false.

Subtracting infinity from infinity yields a result depending on the "degree" of infinity, for example the limit of (x^2 - x) as x goes to infinity is infinity, but the limit of (x^2 - x^3) as x goes to infinity is negative infinity. Usually, subtracting infinity from infinity will yield infinity, negative infinity, or zero. I'm trying to think of a case if it could be a finite number.

**RandomPscho** · 01-5-2007, 02:23 PM

Re: Infinity * Zero = Any Number ARGUE HERE

Isn't that a bad analogy? By saying that infinity - infinity can be anything - anything, you basically equate infinity to anything, which is false.

This is the only analogy I could think of.

**tha Guardians** · 01-6-2007, 07:15 AM

Re: Infinity * Zero = Any Number ARGUE HERE

Sorry Eagle, I hadn't slept in 3 days when I posted that so I basically had no idea what I was really saying, lol. I deleted it, but I still hold my opinion on everything else, so would you please delete your post?

EDIT: I also haven't had a very good education, and I have taught myself every single thing that I know, but it's really hard to learn with just the internet.

*********************************

Originally posted by 3D OGRE 1

it's all relative... you think 1+1=2? hahaha..WRONG

You're right.

1+1=x^2

2+2= (2=1= 2(2) = R2 + 2 = R2,2= ) fish

Numbers are shapes too =)

Infinity * Zero = Any Number ARGUE HERE

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