fruit math

[SKG_Scintill]

Re: fruit math

however if we give the leaf a negative value, does it even exist?

seedless grapes

[danceflashrevo]

Re: fruit math

seedless grapes

okay, seedless grapes. really if we define a normal grape as a grape, then a seedless grape is grape-seed. you're subtracting the positive mass of the seed. Or perhaps a grape is seed + grape and seedless grape is just grape. still positive seed mass being shown in both cases.

[SKG_Scintill]

Re: fruit math

seedless grapes have much higher value when it comes to tastiness

[danceflashrevo]

Re: fruit math

seedless grapes have much higher value when it comes to tastiness

but are we looking at tastiness or just mass? because if we're looking at tastiness we would not be able to find a definite value. in the fruits given (coconuts, apples, and bananas), some people like bananas more than apples more than coconuts, or apples more than bananas more than coconuts, or coconuts more than apples more than bananas! and that's just value comparisons, the values of the "tastiness" of the fruits could be vastly different, not to mention there isn't really a specific way to measure the tastivolts of each fruit for each person.

[gold stinger]

Re: fruit math

tl;dr of Frank's Post:

for all the people saying 17:
the bananas in the final equation are missing a banana each, and there's only 1 half of a coconut.

for all the people saying 14.5:
the apple in apple + banana + banana = 18 doesn't have a leaf like the rest of the apples

for all the people saying 14, 15, or 9:
how? You probably messed up on banana counting, coconut counting, or apple leaf counting somewhere.

edit:
here is answer:

A+A+A=30
30/3 = 10
A = 10
-------------------
a+B+B=18
-------------------
B-C=1
-------------------
(C/2)+A+((B/4)*3) = ??
(C/2)+10+((B/4)*3)

No one can find the answer to a, meaning you can't solve for B
and because you can't solve for B, you can't solve for C.
The only thing that you can solve is A.

[Frank Munoz]

Re: fruit math

tl;dr of Frank's Post:

for all the people saying 17:
the bananas in the final equation are missing a banana each, and there's only 1 half of a coconut.

for all the people saying 14.5:
the apple in apple + banana + banana = 18 doesn't have a leaf like the rest of the apples

for all the people saying 14, 15, or 9:
how? You probably messed up on banana counting, coconut counting, or apple leaf counting somewhere.

edit:
here is answer:

A+A+A=30
30/3 = 10
A = 10
-------------------
a+B+B=18
-------------------
B-C=1
-------------------
(C/2)+A+((B/4)*3) = ??
(C/2)+10+((B/4)*3)

No one can find the answer to a, meaning you can't solve for B
and because you can't solve for B, you can't solve for C.
The only thing that you can solve is A.

OP changed the picture for some reason.
it used to be this

but is now this

though you are right,
it just makes my whole explanation that much more confusing.

thanks ilikexd

[Jtehanonymous]

Re: fruit math

19.5 maybe lol.

The apple with a leaf is 10 since 3 of them make thirty.

Now you have
a + 8B = 18 in the next line.
If I assume losing a leaf decreases the value of the apple with a leaf, a < 10.

If I assume B is an integer, the only possibilities for a single banana are 1 or 2. If B=1 then a = 10, but I think it should be less than 10 since it doesn't have a leaf.

Therefore, each Banana is 2? and then a = 2 so an apple without a leaf is only worth 2.

Moving along...line 3 has
4B - 2CH = 1

Each banana is 2 so 2 coconut halves should be 7.

Then 1 coconut half is 3.5?

Finally looking at the last line:
CH + Apple + 3B = 3.5 + 10 + 3(2) = 19.5


Lots of dumb assumptions and I'm upset with myself for even caring about this to begin with.

cry op playing with my heart nvm

[gold stinger]

Re: fruit math

OP changed the picture for some reason.
it used to be this

Still wouldn't be able to solve shit even if you had the apple with a leaf & apple with no leaf swapping places. You would be able to solve the 2nd & 3rd questions sure, but you're leaving 2 variables in the 4th question. (One variable being ??, the other being the apple with no leaf.)

[leonid]

Re: fruit math

idk how to interpret that odd shaped apple

Actually scratch that lemme look at it again

[Frank Munoz]

Re: fruit math

In the new picture

technically, it's impossible to solve for a numerical answer... still.
because once again, though there are images similar to each other, they still do not match.
meaning they have a totally different(and unknown) value


solve for A
A+A+A=30
3A=30
(3A)/3=30/3
A=10


solve for B
a+B+B=18
a+2B=18
a/2+B=9
B=9-a/2

solve for a
a+B+B=18
a+2B=18
a=18-2B

solve for C
B-C=1
9-2a-C=1
-C=-8+2a
C=8-2a

solve for c
c+A+b=??
c+10+b=??
c+10=??-b
c=??-b-10

solve for b
c+A+b=??
c+10+b=??
10+b=??-c
b=??-c-10

solve for ??
c+A+b=??
??-b-10+10+??-c-10=??
2??-b-c+10=??
2??-b-c=??-10
2??-b=??-10+c
2??=??-10+b+c
??=b+c-10


You can try and speculate what they may average out to.
say,
c=C/2
and
b=B(3/4),
but the apple with no leaf(a) is still nonnumerical
meaning we can't solve for anything other than "A=10".

Another thing is to solve for zero, which i'll expand on later...
in short, there is no 'number' to solve for for now

[ilikexd]

Re: fruit math

I posted a long system of equations on my previous post--the answer is a function of the value of the leaf.

[Frank Munoz]

Re: fruit math

solving for 0
in the new picture

solve for A
A+A+A=30
3A=30
A=10

Solve for 0
a+B+B=18
a+2B-18=0

B-C=1
B-C-1=0

add
a+2B-18=0
to
B-C-1=0

a+3B-19=0

now solve for a
a+3B-19=0
a+3B=19
a=19-3B

then solve for B in the second equation
a+B+B=18
19-3B+B+B=18
19-3B+2B=18
19-B=18
-B=-1
B=1

GREAT, got B
now solve for a in the second equation
a+B+B=18
a+1+1=18
a+2=18
a=16

now back to the third equation
solve for C
B-C=1
1-C=1
-C=0
C=0

now to the last one which is tricky...
lets solve for 10
c+A+b=??
c+10+b=??
c+10=??-b
10=??-b-c
and as we know
10=A
so
A=??-b-c


now lets recap...
A=10 and 10=??-b-c
B=1
C=0
a=16
...

i gotta do my english hw now so i'll continue this ina bit

[Soundwave-]

Re: fruit math

I like how people are making assumptions.

These puzzles trip you into thinking that the point of the puzzle is to make assumptions to reach a certain "solution".

I simply reason that any answer within a field is correct, as the last equation contains three images that are unique to that equation. If you also felt the need to "solve" the images values themselves (which isn't strictly required), then the constraint would also be, of course, that your chosen elements also sum to your chosen solution.

So pi, 42, a matrix, and an expression that when graphed looks like your mom's chubby ass face are all correct answers.

[Frank Munoz]

Re: fruit math

So pi, 42, a matrix, and an expression that when graphed looks like your mom's chubby ass face are all correct answers.

or, anything ranging from -infinity to infinity
as there is no real indication of the images being.. anything really.

....

[MinaciousGrace]

Re: fruit math

that argument is the ultimate cop out

and not even a clever one