Urgent! Need help or will fail Geometry!

[aperson]

Re: RE: Urgent! Need help or will fail Geometry!

Oh, you're right. I was doing it graphically and kept getting different x values, but y would be the same every time because the functions change at the positions of the poles do.

Duh. ._.

C'mon dude, do a bit of functional analysis and it should be plain as day that the y scalar of the function doesn't change.

[Kilgamayan]

RE: Re: RE: Urgent! Need help or will fail Geometry!

Hey it was late and I wasn't thinking properly

[lord_carbo]

RE: Re: RE: Re: RE: Urgent! Need help or will fail Geometry!

Rofl, we were JUST learning stuff like this last week, damnit Jamuko I wanted to look smart.

This is like Algebra I stuff, rofl, geometry?

[Brainmaster07]

The problem doesn't require trig. Assuming distance d and hieghts h(1) and h(2).

You are looking for y at intercept x, set equations equal to x. You need to do this because x is dependant on d, while y is not.
x = (yd)/(h(2))
x = -((y - h(1))d)/(h(1))
If you want to know where I got that, just use some logic. Rise over run times x and negative rise over run times x plus the hieght.
y = (h(2)/d)x
y = -(h(1)/d)x + h(1)


Equate the system of equations to get the general equation
-(y - h(1))/(h(1)) = y/(h(2))
-(h(2)(y-h(1))/h(1) = y
h(2) = y + (h(2)y)/h(1)
h(2)h(1) = h(1)y + h(2)y


Now it's easy, plug in the values
12*6 = 6y + 12y
72 = 18y
y = 4

that general equation will get you the answer for any hieghts, and the distance doesn't matter (Notice it canceled after the substitution). I just perfer to solve problems that way, sorry if it's a bit messy.


Also,

Oh.

See, as soon as you use trig functions, I go "what"

I never took Trig. It makes Calculus very fun.

Woah woah woah, what calc are you in? I can see maybe getting through calc 1 without much knowledge of trig (The focus is much more on derivatives and integrals) but anything past that would be a heck of a lot of fun... Especially those triginometric substitutions, which use trig identities, trig integrals and basic trig manipulations along with everything you've learned about integrals to that point in calc 2 (7.5 in my book). I actually really enjoy those problems, but I'm a nerd .

[Kilgamayan]

He may be in Business Calc. I know our school offers two Calc I/II sections - 133/134, Calc for math/CS majors/engineers, and 123/124, Calc for Business/CJ/Psych/whathaveyou majors. 123 and 124 don't cover Trig at all, but otherwise the two curriculi are exactly the same.

[Squeek]

Calc II.

So far we've done rotations of solids, arclength, the works on that matter. We're moving into Transcendentals and suchnot.

~Squeek