Equations

[benguino]

Re: Equations

100,000,000 = (5^6)*(4^3)*[(9+1)^2]*(8-7)
EDIT 1: 1,000,000,000 = (5^6)*(4^3)*[(9+1)^(2+8-7)]
EDIT 2:10,000,000,000 = (5^6)*(4^3)*(9+1)^[((8!)/(7!))/2]
EDIT 3: 100,000,000,000 = (5^6)*(4^3)*{(9+1)^(7-[sqrt(8)/sqrt(2)])}
EDIT 4: 1,000,000,000,000 = (5^6)*(4^3)*{(9+1)^[((8!)/(7!))-2]}
EDIT 5: 10,000,000,000,000 = (5^6)*(4^3)*(9+1)^((7!)/((8-2)!))
EDIT 6: 100,000,000,000,000 = (5^6)*(4^3)*(8+2)^((9-1)!/(7!))
EDIT 7: 1,000,000,000,000,000 = (5^6)*(4^3)*(9+1)^(sqrt(8)/sqrt(2)+7)

EDIT: Thanks for the 5^6 trick Sax! ^_^
EDIT: I have too much time on my hands right now ._.

[iCeCuBEz v2]

Re: Equations

equations are a tool overall used as a method to find a particular answer.....

Here's an example I had for a question on my "calc III" test.... too vague for me to answer I wanna see what you guys come up with....

Find a symmetrical graph going through the points P(1,2,4) and P(3,4,5

how would YOU guys find the "answer" to "that question"

(specifically it was a test written on paper so I'd have to answer with respect to a "cartesian coordinate plane") (x,y)

[qqwref]

Re: Equations

What does it mean by "symmetrical"? I mean, I'd consider planes and lines to have symmetry, so any plane going through those two points (e.g. z=(x+7)/2) seems to work.

PS: Here's a fun one:
123456789 = ((7+3)^(8+sqrt(4))-1)/(9^2)-6+5

[iCeCuBEz v2]

Re: Equations

yah ok you're confused as well..... I could've made any "graph" I wanted but it was wayyyy to general with its definition of "symmetrical"

It could've had translational symmetry...... symmetry with respect to x-axis..... with respect to y-axis..... rotational symmetry...... across that particular plane in which those points intersect......

I really had no ****ing idea how to answer this question......

If I made a circle on a cartesian coordinate plane.... how would I figure out the radius.....???

I "could" take those two points and create a function that could be written as "symmetrical" across the y-axis.... which would appear as a quadratic function or maybe even a quartic function or something asinine like that..... but was I given enough "information" to conceptualize this problem to a particular formula (or function as what it was defined as in this question.....) this little information could be manipulated into so many "cartesian functions"....... ugh

Wait: I think I got it now..... If I find the distance between those 2 points in the 3 dimensional coordinate plane..... that new found line will create a plane that it is sitting upon.... so I can just use distance formula between those 2 points and then THAT is the radius??? (if i want to graph a circle on a cartesian coordinate plane)

[qqwref]

Re: Equations

If you create a circle (or sphere!) so that the two points are exactly opposite each other on the curve, the radius will be half of the distance between those points (and the center will be the midpoint of the two points). This is getting a bit off-topic, though

[iCeCuBEz v2]

Re: Equations

well it's kinda difficult for me to "draw a sphere" on a piece of paper.... figured he was looking for a circle

[Cavernio]

Re: Equations

http://boardgamegeek.com/boardgame/9938/smath

Played that when I was a kid. The game has 0 though, so if you had 2 in your hand and a division or multiplication sign, you were set. Had a different version than the link though, box looked totally different.