Equations

[Renevatia]

Forgot how many numbers I was using, but I challenge accepted my dad a long time ago, yeah cool childhood, I know.
Use numbers 1-9 and make an equation with any symbol you like in math or even combine them, try keeping it algebra, and make the answer = 1,2,3,4....as far as it goes. Use all 1-9. Hard to explain, goes a little like this.

List as many as you like, or just list a seemingly hard/impossible number to get. Try not listing pointless numbers like 1233312312312445516351351234234.




1=9-8+7-6+5-4-3+2-1
2=(9-8+7-6+5-4-3+2)1
100=(9+1)(3+7)(6-5)+8-(4x2)

[iironiic]

Re: Equations

3=(9-8+7-6+5-4-3+2)+1

xd

[TheSaxRunner05]

Re: Equations

3=9-8+7-6+5-4-3+2+1
4=(9+8+7-6-5-4-3-2)1
5=9+8+7-6-5-4-3-2+1
6=(9+8-7-6+5-4-3+1)*2
Edit://
7=9+8-7-6-5+4+3+2-1
8=(9+8-7-6-5+4+3+2)1
9=9+8+7-6-5-4+3-2-1

Edit2://
1=1^2^3^4^5^6^7^8^9 =p

[benguino]

Re: Equations

10 = 9 + 1 + dₓ(8) + dₓ(7) + dₓ(6) + dₓ(5) + dₓ(4) + dₓ(3) + dₓ(2)

[TheSaxRunner05]

Re: Equations

168,781,726= Sq Root(9)^8 * Sq Root(7)^6 * Sq Root(5)^4 * Sq Root(3)^2 +1

Cant believe that made a whole number lol

[itsmeraph]

Re: Equations

168,781,726= Sq Root(9)^8 * Sq Root(7)^6 * Sq Root(5)^4 * Sq Root(3)^2 +1

Cant believe that made a whole number lol

They are all raised to even powers, so there aren't really any ugly decimals caused by the square roots: that equation is basically 9^4 + 7^3 + 5^2 + 3 + 1

[TheSaxRunner05]

Re: Equations

10 = 9 + 1 + dₓ(8) + dₓ(7) + dₓ(6) + dₓ(5) + dₓ(4) + dₓ(3) + dₓ(2)

Lol

Edit://
0=(-1)9+8+7-6+5-4-3+2

[benguino]

Re: Equations

11 = 6+5+9-8+1-2+7-4-3

Lol

Maybe that's why the OP said Algebra only. If not, I could just spawn as many " + 1"s into the equation by adding "+ dₓ(x)." lmfao

[Renevatia]

Re: Equations

1337= 1327+4+9-5+8-6
9001= 9251-((6-9+8)^3)x sqrt(4)
2012= [563-(2+8)(7-1)]4

[TheSaxRunner05]

Re: Equations

11= 9 + (Sin(8+5)^2 + Cos(7+6)^2) + (Sin(4+1)^2 + Cos(3+2)^2)

Does squaring count as a digit, or can we square as much as we want?

[Renevatia]

Re: Equations

11= 9 + (Sin(8+5)^2 + Cos(7+6)^2) + (Sin(4+1)^2 + Cos(3+2)^2)

Does squaring count as a digit, or can we square as much as we want?

well yes, you can argue that if by that logic sqrt should be counted ^(1/2) but theres a symbol (without numbers shown)for sqrt but no symbol for squares.

[TheSaxRunner05]

Re: Equations

Gah, I was trying to get 1337 legit but I got ...

1335 = (9*8*7*6/4)*(3/2)+1

[Renevatia]

Re: Equations

Gah, I was trying to get 1337 legit but I got ...

1335 = (9*8*7*6/4)*(3/2)+1

1337= (5^3)(2+9)-[(4*6)+8+7-1] if you meant not using any double digits from the 1-9 ;o


1000000= (2^((sqrt(9))!!/3!))-485768*1 , someone try to do this legit too lol.

[TheSaxRunner05]

Re: Equations

Got it, I found out working backwards is so much easier

1337 = ((1*(4+5+6)-8)*3*9+2)*7

Edit:// Yea work backwards

1,000,000 = 5^6*1(8*7+9+4-3-2)

Edit2:// 5^6 is gold for these multiples of 1,000,000 ....

10,000,000 = 5^6*8*(3^4-1)+(9-7-2)

Edit3:// Gah, I almost got my number of games played, too bad the 65* is cheating

21733 = (65*(7/2)*8-9)(3*4)+1

Edit4://
Nvm, got it!

Games played
21,733 = ((6+7*(7/2)*8*5-9)*3*4+1

[Renevatia]

Re: Equations

Got it, I found out working backwards is so much easier

1337 = ((1*(4+5+6)-8)*3*9+2)*7

Edit:// Yea work backwards

1,000,000 = 5^6*1(8*7+9+4-3-2)

Edit2:// 5^6 is gold for these multiples of 1,000,000 ....

10,000,000 = 5^6*8*(3^4-1)+(9-7-2)

Edit3:// Gah, I almost got my number of games played, too bad the 65* is cheating

21733 = (65*(7/2)*8-9)(3*4)+1

Edit4://
Nvm, got it!

Games played
21,733 = ((6+7*(7/2)*8*5-9)*3*4+1

lol nice.

Try your total score lolol.
8533539750