The Homework Help Thread

[Tasselfoot]

alot of places "gifted" really means "amazingly stupid" its kinda like "special". if you were in special education... you were a mo-ron.

[GuidoHunter]

Re: RE: The Homework Help Thread

HVAM... its more the opposite. i know if i posted my questions here, MAYBE 1 person would have any clue about it... so it'd be pointless... but at the same time, i'm very able to help the 13-18 year olds who have questions, as i've had all of that before. except CS... ask LD for that.

not that i really want to. i had my time of algebra and biology... y'all gotta go through it too. and if you think your math is hard: find the integration from -Pi/6 to 2Pi/3 of (sin^2(x))/(sqrt(16-x^4)) that would be a standard problem (i think its solvable, i pulled it out of my head, not a book)

Bad Tassel. BAD! You forgot your dx! ::swats with newspaper::
Anyway, why'd you have to go and make that x^4? That just ruins everything. Then that transcendental function in the numerator threw me off, too. EDIT: Actually, the numerator would resolve without much of a problem.

Had that been root(16-x^2) in the denominator, all that would have collapsed very nicely into 5pi/12, but NooOOOooo, you had to go and make things difficult.

It's been too long since I had calc...

--Guido

http://andy.mikee385.com/

[Tasselfoot]

RE: Re: RE: The Homework Help Thread

exactly the point guido. had to make things fun. and yes... bad on me for forgetting the dx. probably because i never write it down, just realize its implicit. stupid +C too.

[GuidoHunter]

I tried splitting up the denominator into root((4-x^2)(4+x^2)), but I would need to do trig substitution with both sine and tangent, and that just went to hell. Actually, the first factor resolved without much problem, but when I had to introduce a third variable was when I decided to stop.

EDIT: I worked on it some more, and got down to the integral from negative pi over six to two pi over three of sin^2xsec(atanx)dx. I'm not confident with my back substitution, but that's where I ended up, and maybe later I'll have the motivation to attempt that integral.

--Guido

http://andy.mikee385.com

[dinnerroll]

I tried splitting up the denominator into root((4-x^2)(4+x^2)), but I would need to do trig substitution with both sine and tangent, and that just went to hell. Actually, the first factor resolved without much problem, but when I had to introduce a third variable was when I decided to stop.

EDIT: I worked on it some more, and got down to the integral from negative pi over six to two pi over three of sin^2xsec(atanx)dx. I'm not confident with my back substitution, but that's where I ended up, and maybe later I'll have the motivation to attempt that integral.

--Guido

http://andy.mikee385.com

Damn. What grade math is that?

PS: Even though it will mostly be about it the the thread isn't limited to math.

[GuidoHunter]

That's cal II stuff. Well, it could be cal I, but I learned trig substitution in cal II. I took that first semester of my first year of college.

And yeah, I'm always up for helping with homework in whatever way I can.

--Guido

http://andy.mikee385.com

[Tasselfoot]

its the basic stuff of my calc II class. which i'm taking in my junior year of college. heh... starting my math minor late.

[GuidoHunter]

Heh, math majors at SMU coincide very nicely with ME majors. The sooner I get classes out of the way, the sooner I can take the more advanced maths.

--Guido

http://andy.mikee385.com

[JRobin5123]

I'm gonna take a wild guess and say I wouldn't get any help on differential equations (first order for now).

[GuidoHunter]

I took DiffEQ last semester and loved it. Try me. I still have the book and everything.

--Guido

http://andy.mikee385.com

[Boochypa]

Tassel, your problem is unsolvable.

First, that function has no antiderivative. This wouldn't be a problem, except the function also has no value at your upper bound, or anything greater than 2.

It's kind of hard to find the area under the curve when there is no curve.

[GuidoHunter]

Okay, I finally decided to put it into my calculator, and it seems that it is unsolvable, and I was just kidding myself about being able to back-substitute. But, to your credit, Tassel, you did just make it up.

EDIT: It's just your bounds that are bad. The function explodes before you get to 2pi/3.

--Guido

http://andy.mikee385.com

[JRobin5123]

Diff Eqs isn't all that hard (yet), it's just that I have a Russian teacher and haven't been paying attention. What all have you taken math-wise Guido?

[GuidoHunter]

Cal I, II, III, DiffEQ, and I'm currently in Linear Algebra.

--Guido

http://andy.mikee385.com

[Tasselfoot]

oh well.... thats what i get for making somethig up.