Patterns (For the math geeks)

[archbishopjabber]

The rules are simple. Post several numbers of a pattern you developed. The next member in line writes a formula that will result in the pattern, using x as the place in line of the number. For example, if the pattern was 2,4,6,8... the formula would be 2x. Always start the pattern off where x=1. Do not make them to overly complicated... at least in the beginning anyway. In order to post a pattern you must solve the last persons pattern correctly. Make sure your formula fits for all numbers they posted.

The first sequence:

1, 3, 6, 10, 15, 21, 28, 36, 45, 55...

[Doug31]

Re: Patterns (For the math geeks)

Triangular numbers, as in 1+2+3+...+n for the nth term.

Next sequence is
1, 2, 4, 8, 16, 32, 64, 128 (yea, really easy)

[brothaice]

Re: Patterns (For the math geeks)

y=2n


1, 3, 5, 7, 11, 13, 17, 19, 23...

I think all those are right.

[Doug31]

Re: Patterns (For the math geeks)

Are those supposed to be primes? If so, 2 should be on the list, and not 1.

Edit: and mine was NOT 2n, it was 2^n.

[Fantasticone]

Re: Patterns (For the math geeks)

+2

.3333, .1111, .0370, .0123, .0041

[ledwix]

Re: Patterns (For the math geeks)

^^^^^^^^^^
a(n) = (1)/(3^n)

new: 1, 4, 27, 256, 3125, 46656, 823543

[Doug31]

Re: Patterns (For the math geeks)

x^x

Next one is:
1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144...

[Fantasticone]

Re: Patterns (For the math geeks)

Add all previous numbers.

5000, 3125, 685.871, 76.293, 5.12

[Doug31]

Re: Patterns (For the math geeks)

It's not add ALL previous numbers, it's just adding the most recent 2.

[Fantasticone]

Re: Patterns (For the math geeks)

Add all previous numbers.

5000, 3125, 685.871, 76.293, 5.12

Cough cough.

[brothaice]

Re: Patterns (For the math geeks)

Triangular numbers, as in 1+2+3+...+n for the nth term.

Next sequence is
1, 2, 4, 8, 16, 32, 64, 128 (yea, really easy)

1 x 2 = 2

2 x 2 = 4

4 x 2 = 8

8 x 2 = 16

16 x 2 = 32

32 x 2 = 64

64 x 2 = 128

Let n represent the previous number in the sequence.

f(n)=2n

Doug or someone else please tell me how that is wrong.
Dont mean to bitch i just wanna know XD

[EI_Tizzy]

Re: Patterns (For the math geeks)

You are partly correct.

The equation for the NEXT term in this series is 2n, but the series as a whole is defined by 2^n.

Also, I have no clue on Fantasticone's one. My guess is that there is none XD

[Fantasticone]

Re: Patterns (For the math geeks)

500{1/(.n/n)}^n

[brothaice]

Re: Patterns (For the math geeks)

You are partly correct.

The equation for the NEXT term in this series is 2n, but the series as a whole is defined by 2^n.

Also, I have no clue on Fantasticone's one. My guess is that there is none XD

Oh, i thought thats what we were finding, lol

[Doug31]

Re: Patterns (For the math geeks)

500{1/(.n/n)}^n

That was too hard.