When someone fixes the proof I'll post another one in which I break the laws again.
P.S. If you think this is too easy for you don't ruin it for others. Let them figure it out.
Proof 1: 3=2
-6 = -6
9 - 15 = 4 - 10
9 + (25/4) - 15 = 4 + (25/4) - 10
(3 - 5/2)(3 - 5/2) = (2 - 5/2)(2 - 5/2)
(3 - 5/2)² = (2 - 5/2)²
3 - 5/2 = 2 - 5/2
3 = 2
Proof 2: 2=1
a = b
a² = ab
a² - b² = ab - b²
(a - b)(a + b) = b (a - b)
a + b = b
2b = b
2 = 1
Proof 3: 1=-1
-1 = -1
1/-1 = -1/1
√(1/-1) = √(-1/1)
√1 / √-1 = √-1 / √1
√1 * √1 = √-1 * √-1
√1 = √-1
1 = -1
Alternate version of Proof 3:
1 = √1 = √(-1)(-1) = √-1 * √-1 = -1
Proof 4: 0=1
0 = 0 + 0 + 0 + 0 + ...
0 = (1 - 1) + (1 - 1) + (1 - 1) + (1 - 1) + ...
0 = 1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + ...
0 = 1 + 0 + 0 + 0 + ...
0 = 1
Proof 5: 1=0
x = 1
(d/dx) x = (d/dx) 1
1 = 0
Proof 6: 2=1
x² = x * x = x + x + x + x ... (x times)
(d/dx) x² = (d/dx) x + x + x + x ... (x times)
2x = 1 + 1 + 1 + 1 ... (x times)
2x = x
2 = 1
Proof 7: Sum of all positive integers is negative.
S = 1 + 2 + 3 + 4 + 5 + 6 + 7 + ...
A = 1 - 2 + 3 - 4 + 5 - 6 + 7 - ...
S-A = (1-1) + (2-(-2)) + (3-3) + (4-(-4)) + ...
= 4 + 8 + 12 + 16 + ...
= 4S
S+A = (1+1) + (2+(-2)) + (3+3) + (4+(-4)) + ...
= 2 + 6 + 10 + 14 + ...
= 2 + (4+2) + (8+2) + (12+2) + ...
= 4S + (2+2+2+2+...)
(S-A) + (S+A) = 2S = 8S + (2+2+2+2+...)
-6S = (2+2+2+2+...)
S = (-1/6)(2+2+2+2+...)
Mind blown yet?
P.S. If you think this is too easy for you don't ruin it for others. Let them figure it out.
Proof 1: 3=2
-6 = -6
9 - 15 = 4 - 10
9 + (25/4) - 15 = 4 + (25/4) - 10
(3 - 5/2)(3 - 5/2) = (2 - 5/2)(2 - 5/2)
(3 - 5/2)² = (2 - 5/2)²
3 - 5/2 = 2 - 5/2
3 = 2
Proof 2: 2=1
a = b
a² = ab
a² - b² = ab - b²
(a - b)(a + b) = b (a - b)
a + b = b
2b = b
2 = 1
Proof 3: 1=-1
-1 = -1
1/-1 = -1/1
√(1/-1) = √(-1/1)
√1 / √-1 = √-1 / √1
√1 * √1 = √-1 * √-1
√1 = √-1
1 = -1
Alternate version of Proof 3:
1 = √1 = √(-1)(-1) = √-1 * √-1 = -1
Proof 4: 0=1
0 = 0 + 0 + 0 + 0 + ...
0 = (1 - 1) + (1 - 1) + (1 - 1) + (1 - 1) + ...
0 = 1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + ...
0 = 1 + 0 + 0 + 0 + ...
0 = 1
Proof 5: 1=0
x = 1
(d/dx) x = (d/dx) 1
1 = 0
Proof 6: 2=1
x² = x * x = x + x + x + x ... (x times)
(d/dx) x² = (d/dx) x + x + x + x ... (x times)
2x = 1 + 1 + 1 + 1 ... (x times)
2x = x
2 = 1
Proof 7: Sum of all positive integers is negative.
S = 1 + 2 + 3 + 4 + 5 + 6 + 7 + ...
A = 1 - 2 + 3 - 4 + 5 - 6 + 7 - ...
S-A = (1-1) + (2-(-2)) + (3-3) + (4-(-4)) + ...
= 4 + 8 + 12 + 16 + ...
= 4S
S+A = (1+1) + (2+(-2)) + (3+3) + (4+(-4)) + ...
= 2 + 6 + 10 + 14 + ...
= 2 + (4+2) + (8+2) + (12+2) + ...
= 4S + (2+2+2+2+...)
(S-A) + (S+A) = 2S = 8S + (2+2+2+2+...)
-6S = (2+2+2+2+...)
S = (-1/6)(2+2+2+2+...)
Mind blown yet?







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