well i dont know if this is right but i looked it up xp
c = i gives the sequence 0, i, (−1 + i), −i, (−1 + i), −i…, which is bounded, and so it belongs to the Mandelbrot set.
dont really know what that means though hahaha
BTW i am going to be studying this all night now in an attempt to further my limited knowledge
chances are it will end in catastrophe (or i will just give up)
Last edited by xealix; 12-15-2008, 06:54 PM.
Reason: to add slight amounts of joy to the world (ragle fragle)
I will use musical lyrics for my siggy.
"In the cradle we are helpless, but on our feet we are fatal" - The Dear Hunter
BTW i am going to be studying this all night now in an attempt to further my limited knowledge
chances are it will end in catastrophe (or i will just give up)
I can gather from this statement that you didn't work on it at all.
I did. . .for like 10 minutes. Hey what can i say i get bored easily and i don't have a math teacher to help me. Sometime i really miss my math teachers Xp
I will use musical lyrics for my siggy.
"In the cradle we are helpless, but on our feet we are fatal" - The Dear Hunter
That is, a complex number, c, is in the Mandelbrot set if, when starting with z0=0 and applying the iteration repeatedly, the absolute value of zn never exceeds a certain number (that number depends on c) however large n gets.
cause i wont get this. . .
maybe 0?? or what ever # applies
hmmm. . .
I will use musical lyrics for my siggy.
"In the cradle we are helpless, but on our feet we are fatal" - The Dear Hunter
A mandelbrot set requires that |c| <2 (if |z|>2, then |z^2 +c | ≥ |z^2|-|c| > 2|z|-|c|. If |z|>|c|, then 2|z| - |c| > |z|. so, if |z| > 2 and |z| > |c|, then |z^2 + c| > |z|, so the sequence is increasing, and eventually goes to infinity for |c| >2). |i| = 1, which is less than 2. Thus, c = i is contained within the mandelbrot set.
Last edited by sumzup; 12-15-2008, 07:57 PM.
Reason: spelled infinity wrong
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